Pete's Blog

The following are the first fifty terms of a sequence:

1, 2, 4, 5, 7, 9, 10, 12, 14, 16, 17, 19, 21, 23, 25, 26, 28, 30, 32, 34, 36, 37, 39, 41, 43, 45, 47, 49, 50, 52, 54, 56, 58, 60, 62, 64, 65, 67, 69, 71, 73, 75, 77, 79, 81, 82, 84, 86, 88, 90, . . .

Same idea as the other sequences. Describe the pattern of the sequence. If you use a search engine, please don't submit it in the comments.

If it hasn't been solved by Thursday, I'll give a hint. Also, if you ask a polar question (i.e., a yes/no question), I will probably answer it if it relates to this sequence.

I'll post the solution on next week's sequence.

Last week's sequence (1, 7, 10, 13, 19, 23, 28, 31, 32, 44, . . .) was the list of numbers whose iteration of the sum of the square of their digits converged to 1. E.g., 1²=1, so 1 is in the sequence. E.g., 2→2²=4→4²=16→1²+6²=37→3²+7²=58→5²+8²=89→8²+9²=145→1²+4²+5²=42→4²+2²=20→2²+0²=4 and from here the iteration loops infinitely through the cycle 4, 16, 37, 58, 89, 145, 42, 20, thus never reaching 1. So, 2 is not in the sequence. E.g., 13→1²+3²=10→1²+0²=1. So 13 is in the sequence. It was not solved.